Solution : The Review of CET Sample Paper

1. c

2. d

3. c From clues IV & VI we conclude that F – G – H are the recruitment agents that should be included. Hence only one combination is possible.

4. a

5. b From solutions 68 & 69 we know that F, G and B all can go with C, hence right answer should be (b).

Directions for 6 to 11: Refer to the following table for the following solutions. The following table gives the moves that can be made for the mentioned conditions. The underlined positions indicate your position after nth move.

6. d

7. c

8.d By moving a step anticlockwise in the first move, you reach at 12 O’clock. From here you can reach

a 10’O Clock through 12 – 11 - 10

b 5 ‘O clock through 12 – 6 – 5

c 7 ‘O Clock through 12 – 6 – 7.

But you cannot reach 6 ‘O Clock. Hence (4).

9. b

10. c Your mother’s husband ? your father. Your father’s sister ? your aunt. So, the lady’s aunt is the man’s aunt ? the man and the lady are brother and sister.

11. c M is the maternal uncle of R means m is the brother of R‘s mother (say K) i.e., M + K – R.

Direction for 12 to 13: Refer to the following information for the following solutions. We are given that A visited at 8 O’clock. Now from III we conclude that A visited at 8 p.m. Now from I we concluded that B has to visit at 9 a.m. otherwise nobody will be able to visit in between A & B. Now if D were to visit at 11 p.m. then condition IV will get violated hence we concluded that D visited at 11 a.m. and C visited at 10 p.m. From here all the questions are answered.

12. b

13. c

Directions for 14 to 19: Refer to the following information for the following solutions. The ratio of the values of Dollar: Pound: DM, for July month are calculated as below. Table of exchange rate fluctuation between DM/Pound during the sex months, can be calculated as,

Similar approach is applied to arrive at following table.

From this all the questions can be answered.

14. c Directly looking at the table.

15. a Directly looking at the table.

16. d To purchase maximum number of pounds,

Pounds : DM ratio should be maximum or

DM : Pounds ratio should be minimum.

17. b The cost per kg of tea is Rs. 64. Therefore, the cost per tonne of tea is 64 X 1000 = Rs. 64,000.

100 mn = Rs. 48 X 100 mn = Rs. 4800 mn. Rs. 4800 X 106

No. of tones of tea that needs to be exported =

64000

4800000000

= 75000 tonnes.

18. c From the table it is clear that 10 Pounds = 24.928 DM = Rs. 747.84 ? Rs. 747.80.

19. a Highest percentage change was in Nov. – Dec. and was equal to

1 54

0 04

.

.

X 100 = 2.60%

20.d Because the minority might consist of thousand of people, the opposition might not be inconsistent with the speaker’s remarks.

21. b

22. b If 20% work in the technical level and within, that means 80% are in the outer two layers. ? 8% of 355 = 284. From this, subtract the number of people in the peripheral layer (54), to get the answer = 230.

23. a The number must be equal to or more than 36 considering the 3 security personnel rule. ? Choices b and d are invalid. Out of the 110 people there are already 54 in the peripheral level, thus there cannot be more than 56 in the security level. This eliminates choice c of 58, leaving one choice a

24. d A drop of 12 people in peripheral is equivalent to 50% of the complete lay-offs, which then must be 12 x 2 = 24, which is 15% of the original population, which must be: 24/0.5 = 160. Hence, d

25. b The total number of people who do not need security clearance are 54 + 48 = 102. ? Percentage of people who do need security clearance = 360

360 ? 102 = 100% ? 72%.

Hence b

Q. 26 – 28. From condition # 1 and # 2, either

I. Mr. Gupta won one game, Mrs. Gupta won one game, and Mr. Sharma won one game; or

II. Mr. Gupta won two games and Mrs. Gupta won one game; or

III. Mr. Gupta won two games and Mrs. Sharma won one game.

If I is correct, then : Form (3), Mr. Sharma beat Mrs. Sharma in the first game. Then, only Mr. Sharma could have lost to Mr. Gupta or Mrs. Gupta in the second game. Then, from

(3), no one could have played against the last winner in the last game. So, I is not correct.

II cannot be correct from (3).

So, III is correct. If Mrs. Sharma won the first game, then she beat Mr. Sharma in that game, from (3). But then, from (3), no one could have played against Mr. Gupta in the second game. So, Mr Gupta won the first game against Mrs. Gupta, from (1). Then, Mr. Gupta beat Mr. Sharma in the second game. The Mrs. Sharma beat Mr. Gupta in the third game. So, only Mrs. Sharma did not lose a game.

26. b 27. b 28. a

29. d 30. c 31. a 32. b 33. c

34. b 35. b 36. d 37. a 38. c 39.b 40. d

41. 42. c 43. b 44. d 45.c 46. a

47-48. The second resident always speaks truth (so, not a govt. official) First speaker may speak truth (IS not & denies being a govt. official) or may tell a lie (is a govt. official but denies being one) – in either case denying being a govt. official. If first resident speaks truth the third one tells a lie and vice-versa.

47. c

48. d

49. (3) History of Modern Europe (HME) + American History (AH) = 90 + 90 = 180, but there are only 120 students. Thus, at least 60 students selected both of the above subjects. HME and AM + Ancient Indian History (AIH) = 60 + 105 = 165. Thus, again, as there are only 120 students, at least 45 would have taken all three of above. Using the same logic, (45 + 105) – 120 = 30 students at least would select all the four subjects.

50. b 51. d

52.d By conditions (vi) and (vii) together, (4) is necessarily true. Hence, (d).

53.d If E is midway between B and C, then the distance between B and E is ¼ mile and between E and C is ¼ mile. Then: (a) is true by condition (iii); (b) is true by conditions and (ii) and (iii); (c) is true by condition (ii); (d) is false, as the distance from D to E is 1 mile, E to C is ¼ mile and C to A is ½ mile, which is less than 2 miles. Hence (d).

54.c By conditions (vi) and (vii), option (b) will make two roads coincide

55.b Diagrammatically, representing data in question and conditions (iv) and (v), J and H will be ½ mile apart. Hence (b).

56.c As explained in !. 117,

For answers to questions 57 to 59: The given information can be tabulated as follows:

Now, all the questions can be answered.

57.c The married ladies are B and E.

58.b The married couples are AB and CE.

59.d The unmarried lady i.e., D wears a gray/blue coloured dress

Now, we can answer all the questions.

60.c No play is shown on Monday. Hence, (3)

61.a Play R is shown on Friday.

62.c The last play to be shown is P

63.b Two plays are shown between S and U

64.c ‘2’ is located on the 8th position.

65.b ‘a’ and ‘b’ are the 2 letters that are immediately preceded as well as followed by numbers

66.c The 13th element from the right is ‘9’. Third to the right or ‘9’ is (2).

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